The force delivered by a coil spring is a function of the spring constant ( a measure of the spring stiffness ) and the distance through which it moves, i.e., F = kx. If the spring is still moving through the same distance, which I imagine it would, therefore no change in x, and the spring is unchanged, then k remains the same, hence the Force remains unchanged. If you now use Newton's second law, F = ma, the spring-mass is unchanged, and the Force we have just calculated, which we substitute in, then the acceleration of the spring is what it was before.
So unless you somehow compressed it more than it should be, then all remains as it was. If there was a degree of friction between the surface of the spring which worked to reduce the acceleration, and now it is clean and moving with less friction, then that is likely your answer.
Ron.